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  1. #include <stdio.h>
  2. void fibo(int k){
  3. 	int m=1,n,l=1,p;
  4. 	if((k==0)||(k==1)){printf("1");}
  5. 	else {for(n=2;n<k+1;n++){
  6. 		p=m;
  7. 		m=m+l;
  8. 		l=p;
  9. 	}
  10. 	printf("%d",m);
  11. 	}
  12. } 
  13.  
  14. int fibo1(int k){
  15. 	int m;
  16. 	if(k==0){return 1;}
  17. 	if(k==1){return 1;}
  18. 	else{
  19. 		m=fibo1(k-1)+fibo1(k-2);
  20. 		return m;
  21. 	}
  22. }
  23.  
  24. int main(void) {
  25. 	int l;
  26. 	fibo(0);
  27. 	l=fibo1(0);
  28. 	printf("\n%d",l);
  29. 	//fibo1 が再帰 fiboがfor文
  30. 	return 0;}
Success #stdin #stdout 0s 5324KB
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https://ideone.com/zIU3fI
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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