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  1. #include <stdio.h>
  2.  
  3. #define NUM 10
  4.  
  5. int main()
  6. {
  7.     int a[NUM];
  8.     int i;
  9.  
  10.     a[0] = 3;
  11.     a[1] = 6;
  12.  
  13.     for (i = 2; i < NUM; i++)
  14.     {
  15.         a[i] = a[i - 1]+a[i-2]*2-3;
  16.     }
  17.  
  18.     printf("数列の最初の10項目:\n");
  19.     for (i = 0; i < NUM; i++)
  20.     {
  21.         printf("a(%d) = %d\n", i + 1, a[i]);
  22.     }
  23.  
  24.     return 0;
  25. }
  26.  
Success #stdin #stdout 0.01s 5288KB
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stdin
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Standard input is empty
stdout
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数列の最初の10項目:
a(1) = 3
a(2) = 6
a(3) = 9
a(4) = 18
a(5) = 33
a(6) = 66
a(7) = 129
a(8) = 258
a(9) = 513
a(10) = 1026
https://ideone.com/wSG39u
language:
C (gcc 8.3)
created:
16 hours ago
visibility:
public

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