#This is my PYTHON program
import math;
K = 22.50;
L = 7.5;
x1 = 0.234;
x2 = 1.426;
x3 = -0.414;
x=y=a=b=float();
print('Please enter value for x/n');
x=float(input());
print("x=,", x)
if x < -2.84:
print('ERROR: the negative value in square root')
else:
a = math.pow((math.exp(-0.5 * math.log(K)) - L * math.log(x)), 2)
print('Result is a=', a)
if x <= 0:
print('ERROR: division by zero or negative value in log')
else:
b = (math.log(x) / math.log(10)) * math.exp(x)
print('Result is b=', b)
if (math.pow(a, 2) + math.pow(b, 2)) == 0:
print('ERROR: division by zero')
else:
y = (4 * a + 3 * b) / (math.pow(a, 2) + math.pow(b, 2))
if a <= 0:
y = math.abs(a - b)
else:
y = math.sqrt(y + b)
print('Result is y =', y)
print('Result is y =', y)
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