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  1. #include <stdio.h>
  2. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod){
  3. 	*sum=x+y;
  4. 	*diff=(x>y)?(x-y):(y-x);
  5. 	*mul=x*y;
  6. 	*mod=x/y;
  7. }
  8. int main(void) {
  9. 	int x,y,sum,diff,mul,mod;
  10. 	scanf("%d %d",&x,&y);
  11.  
  12. 	cal(x,y,&sum,&diff,&mul,&mod);
  13.  
  14. 	printf("和:%d\n",sum);
  15. 	printf("差:%d\n",diff);
  16. 	printf("積:%d\n",mul);
  17. 	printf("商:%d\n",mod);
  18.  
  19.  
  20. 	return 0;
  21. }
  22.  
Success #stdin #stdout 0s 5288KB
comments (?)
stdin
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4 2
stdout
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和:6
差:2
積:8
商:2
https://ideone.com/l3bna5
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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