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  1. #include <stdio.h>
  2.  
  3. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod);
  4.  
  5. int main() {
  6.     int x, y;
  7.     int sum, diff, mul, mod;
  8.  
  9.     printf("x と y を入力してください: ");
  10.     scanf("%d %d", &x, &y);
  11.     cal(x, y, &sum, &diff, &mul, &mod);
  12.  
  13.     printf("x + y = %d\n", sum);
  14.     printf("|x - y| = %d\n", diff);
  15.     printf("x * y = %d\n", mul);
  16.     printf("x / y = %d\n", mod);
  17.  
  18.     return 0;
  19. }
  20. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod) {
  21.     *sum = x + y;
  22.     *diff = (x > y) ? (x - y) : (y - x);
  23.     *mul = x * y;
  24.      *mod = x / y;  
  25. }
Success #stdin #stdout 0s 5260KB
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stdout
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x と y を入力してください: x + y = 8
|x - y| = 2
x * y = 15
x / y = 0
https://ideone.com/cyj41V
language:
C (gcc 8.3)
created:
7 days ago
visibility:
public

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