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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	//関数の中だけを書き換えてください
  5. 	//回文になっているとき１を返す
  6. 	//回文になっていないとき０を返す
  7. 	char t[100];
  8. 	int i,count=-1;
  9. 	for(i=0; s[i] !='\0'; i++){
  10. 		count ++;
  11. 		t[i] = s[i];
  12. 	}
  13. 	t[i]='\0';
  14.  
  15. 	for(i=0; s[i] !='\0'; i++){
  16. 		if(s[i] != t[count]){
  17. 			return 0;
  18. 		}
  19. 		count--;
  20.  
  21. 	}
  22. 	return 1;
  23. }
  24.  
  25. //メイン関数は書き換えなくてよいです
  26. int main(){
  27.     char s[100];
  28.     scanf("%s",s);
  29.     printf("%s -> %d\n",s,isPalindrome(s));
  30.     return 0;
  31. }
  32.  
Success #stdin #stdout 0s 5280KB
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https://ideone.com/VrJ8SS
language:
C (gcc 8.3)
created:
14 hours ago
visibility:
public

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