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  1. #include <stdio.h>
  2. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod){
  3. *sum=x+y;
  4. if(x-y<0)
  5. *diff=-1*(x-y);
  6. else
  7. *diff=x-y;
  8. *mul=x*y;
  9. if(y!=0)
  10. *mod=x/y;
  11. else
  12. *mod=0;
  13. }
  14.  
  15.  
  16.  
  17. int main(void) {
  18. 	int x,y,sum,diff,mul,mod;
  19. 	scanf("%d %d",&x,&y);
  20. 	cal(x,y,&sum,&diff,&mul,&mod);
  21. 	printf("和 %d、差 %d、積 %d、商 %d",sum,diff,mul,mod);
  22.  
  23.  
  24. 	return 0;
  25. }
  26.  
Success #stdin #stdout 0.01s 5288KB
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stdin
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3 2
stdout
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和 5、差 1、積 6、商 1
https://ideone.com/UpC6rF
language:
C99 (gcc 8.3)
created:
1 day ago
visibility:
public

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