#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
 
int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
 
    int t;
    cin >> t;
    while (t--) {
        ll n, k;
        int p1, p2;
        cin >> n >> k >> p1 >> p2;
        p1--; 
        p2--;
        vector<int> perm(n + 1);
        vector<ll> arr(n + 1);
 
        for (int i = 1; i <= n; i++) {
            cin >> perm[i];
        }
        for (int i = 1 ; i <= n; i ++) {
            cin >> arr[i]; 
        }
 
        ll p1max = 0, p2max = 0;
        ll p1sum = 0, p2sum = 0;
        ll steps = min<ll>(k, n);
        int cur1 = p1, cur2 = p2;
 
        for (int i = 0; i < steps; i++) {
            // Add the “chain contribution” from staying at cur1 for (k - i) more steps:
            p1max = max(p1max, p1sum + (k - i) * arr[cur1]);
            // Then walk to the next in the cycle:
            p1sum += perm[cur1];
            cur1 = perm[cur1];
 
            p2max = max(p2max, p2sum + (k - i) * arr[cur2]);
            p2sum += arr[cur2];
            cur2 = perm[cur2];
        }
 
        if (p1max > p2max) {
            cout << "Bodya\n";
        } else if (p2max > p1max) {
            cout << "Sasha\n";
        } else {
            cout << "Draw\n";
        }
    }
    return 0;
}
 

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10
4 2 3 2
4 1 2 3
7 2 5 6
10 8 2 10
3 1 4 5 2 7 8 10 6 9
5 10 5 1 3 7 10 15 4 3
2 1000000000 1 2
1 2
4 4
8 10 4 1
5 1 4 3 2 8 6 7
1 1 2 1 2 100 101 102
5 1 2 5
1 2 4 5 3
4 6 9 4 2
4 2 3 1
4 1 3 2
6 8 5 3
6 9 5 4
6 1 3 5 2 4
6 9 8 9 5 10
4 8 4 2
2 3 4 1
5 2 8 7
4 2 3 1
4 1 3 2
6 8 5 3
2 1000000000 1 2
1 2
1000000000 2