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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.     int a = 3;  // a₀の初期値
  5.     int n = 0;
  6.  
  7.     while (a <= 10000) {
  8.         a = 2 * a - 1;
  9.         n++;
  10.     }
  11.  
  12.     printf("初めて10000を超えるときのa[%d] = %d\n", n, a);
  13.  
  14.     return 0;
  15. }
  16.  
  17.  
Success #stdin #stdout 0.01s 5288KB
comments (?)
stdin 
Standard input is empty
stdout 
初めて10000を超えるときのa[13] = 16385
https://ideone.com/N7wJi3
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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