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  1. #include <stdio.h>
  2.  
  3. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod) {
  4.     *sum = x + y;                  
  5.     *diff = (x > y) ? (x - y) : (y - x);
  6.     *mul = x * y;                   
  7.     *mod = x / y;                   
  8. }
  9. int main() {
  10.     int x, y;
  11.     int sum, diff, mul, mod;
  12.  
  13.     printf("x を入力してください: ");
  14.     scanf("%d", &x);
  15.  
  16.     printf("y を入力してください: ");
  17.     scanf("%d", &y);
  18.  
  19.     cal(x, y, &sum, &diff, &mul, &mod);
  20.  
  21.     printf("和  = %d\n", sum);
  22.     printf("差  = %d\n", diff);
  23.     printf("積  = %d\n", mul);
  24.     printf("商(切り捨て) = %d\n", mod);
  25.  
  26.     return 0;
  27. }
  28.  
Success #stdin #stdout 0s 5320KB
comments (?)
stdin
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5
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stdout
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x を入力してください: y を入力してください: 和  = 11
差  = 1
積  = 30
商(切り捨て) = 0
https://ideone.com/INJa7C
プロ演III　第2回提出課題1
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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