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  1. #include <stdio.h>
  2.  
  3. int main(){
  4. 	int a,n,m[10],i,p=1,result=0;
  5. 	scanf("%d %d",&a,&n);
  6. 	for(i=1;i<=n;i++){
  7. 		p=p*a;
  8. 		m[i-1]=p;
  9. 		result=result+m[i-1];
  10. 	}printf("%d",result);
  11. 	return 0;
  12. }
Success #stdin #stdout 0.01s 5280KB
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https://ideone.com/CrMAU3
language:
C (gcc 8.3)
created:
13 hours ago
visibility:
public

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