import re
 
def find_ips(inp):
    '''
    Returns a list of ip addresses of the form 'x.x.x.x' that are in the input
    string and are separated by at least some whitespace.
    >>> find_ips('this has one ip address 127.0.0.1')
    ['127.0.0.1']
    >>> find_ips('this has zero ip addresses 1.2.3.4.5')
    []
    '''
    pattern = r"^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$" 
    iplist = [match[0] for match in re.findall(pattern, inp)]
    return iplist
 
ips = []
ips = find_ips('basjlcbndilsfn 1.2.3.4.5')
print ips 
 

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