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  1. #include <stdio.h>
  2. int main(void) 
  3. {
  4. 	int a,b,c;
  5. 	printf("整数と演算を表す数字を入力:\n"); scanf("%d %d %d",&a,&b,&c);
  6. 	switch(c)
  7. 	{
  8. 		case 1:printf("%d + %d = %d",a,b,a+b); break;
  9. 		case 2:printf("%d - %d = %d",a,b,a-b); break;
  10. 		case 3:printf("%d × %d = %d",a,b,a*b); break;
  11. 		case 4:
  12. 			if(b!=0 && a%b != 0)
  13. 			{
  14. 				printf("%d ÷ %d = %d余り%d",a,b,a/b,a%b); break;
  15. 			}
  16. 			else if(b != 0 && a%b == 0)
  17. 			{
  18. 				printf("%d ÷ %d = %d",a,b,a/b); break;
  19. 			}
  20. 			else
  21. 			{
  22. 				printf("error"); break;
  23. 			}
  24. 		default: printf("error");
  25. 	}
  26. 	return 0;
  27. }
Success #stdin #stdout 0s 5292KB
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整数と演算を表す数字を入力:
error
https://ideone.com/BiSnBU
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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