#include <iostream>
using namespace std;
/*
Declarăm și citim de la tastatura variabila “a”.
 
Declarăm o variabila ajutătoare “odd” pe care o initializam cu valoarea zero, în care contorizam toate cifrele care nu respecta condițiile cerute.
 
     3. Ne folosim de o alta structura decizionala care verifica ca “a” sa fie egal cu “0”: În caz afirmativ: “odd” va lua valoarea unu.
 
     4. Ne folosim de o structura repetitiva a cărei condiție de rulare verifica ca “a” sa fie mai mare decat zero:
Ne folosim de o structura decizionala care verifica ca cifra curentă este mai mica decat valoarea patru sau dacă cifra curentă este impara: In caz afirmativ, incrementam valoarea variabilei “odd”.
Ne asigurăm ca tăiem ultima cifra din “a”.
 
     4. Ne folosim de o alta structura decizionala care verifica ca variabila “odd” sa fie egala cu zero. In caz afirmativ, afisam textul “DA”, altfel afisam textul “NU”. 
*/
 
const int TEN = 10;
 
int main() {
	int a;
	cin >> a;
	int odd = 0;
	if (a == 0) {
		odd = 1;
	}
	while (a > 0) {
		if (a % TEN < 4 || a % TEN % 2 != 0) {
			++odd;
		}
		a /= TEN;
	}
	if (odd == 0) {
		cout << "DA";
	} else {
		cout << "NU";
	}
	return 0;
}

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CgoKCgogCiAKCgoKCgo0NDQ0NDQ0IC0mZ3Q7IERBCgo=

 
 





4444444 -> DA