#include <iostream>
using namespace std;
int main() {
int M, N;
cin >> M >> N;
cout << (M+N)*(M+N-1)/2 + (min(M,N)-1)*min(M,N)/2 << endl;
return 0;
}
/*
2 7
6 5
8 4
9 3
10 1
S(n) = 1+2+3+..+n = n*(n+1)/2
2 6 8 9 10
7 5 4 3 1
1+2+3+4+5+7 = 1+2+3+4+5+6 + 1 = S(6)+S(1)
6 = 2+5-1
1 = min(2,5)-1
1 6 8
7 4 9
5 3 2
1+2+3+5+7 = 1+2+3+4+5 + 1+2 = S(5)+S(2)
5 = 3+3-1
2 = min(3,3)-1
S(M+N-1) + S(min(M,N)-1)
*/
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