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  1. #include <stdio.h>
  2.  
  3. int daysInMonth[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  4.  
  5. int leap(int year) {
  6.     if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
  7.         return 1;
  8.     } else {
  9.         return 0;
  10.     }
  11. }
  12.  
  13. int numberofdays(int year, int month, int date) {
  14.     int sum = 0;
  15.     for (int i = 1; i < month; i++) {
  16.         sum += daysInMonth[i];
  17.     }
  18.     if (leap(year) && month > 2) {
  19.         sum += 1;
  20.     }
  21.     sum += date;
  22.     return sum;
  23. }
  24.  
  25. int main() {
  26.     int year, month, day;
  27.     scanf("%d/%d/%d", &year, &month, &day);
  28.     int result = numberofdays(year, month, day);
  29.     printf("%d\n", result);
  30.     return 0;
  31. }
Success #stdin #stdout 0s 5312KB
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2025/6/19
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https://ideone.com/5UlqbU
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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