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  1. #include <stdio.h>
  2. int fib1(int n){
  3.      if(n==0){
  4.         return 0;}
  5.      if(n==1){
  6.         return 1;}
  7.      int a =0;
  8.      int b =1;
  9.      int c =0;
  10.      for(int i=2;i<=n ;i++){
  11.          c=a+b;
  12.          a=b;
  13.          b=c;
  14.    }
  15.      return c;
  16. }
  17. int fib2(int n){
  18.      if(n==0){ 
  19.         return 0;}
  20.      if(n==1){
  21.         return 1;}
  22.     int f[n+1];
  23.     f[0]=0;
  24.     f[1]=1;
  25.     for(int i=2;i<=n ;i++){
  26.       f[i]=f[i-1]+f[i-2];
  27.     }
  28.      return f[n];
  29. }
  30. int fib3(int n){
  31.      if(n==0){ 
  32.         return 0;}
  33.      if(n==1){
  34.         return 1;}
  35.     return fib3(n-1)+fib3(n-2);
  36. }
  37. int main(void) {
  38.    int n;
  39.    scanf("%d",&n);
  40.  
  41.    printf("fib1:%d\n",fib1(n));
  42.    printf("fib2:%d\n",fib2(n));
  43.    printf("fib3:%d\n",fib3(n));
  44. 	// your code goes here
  45. 	return 0;
  46. }
  47.  
Success #stdin #stdout 0.01s 5320KB
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stdin
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5
stdout
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fib1:5
fib2:5
fib3:5
https://ideone.com/4NsnNo
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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